Escaping spaces in arguments to shell script

[stevenerat at yahoo.com (Steven Erat)]

Would someone kindly suggest the solution to passing input parameters to a
shell script where the arguments may contain spaces?  

Please refer to the example below.

Thank you,
Steven Erat


[auser at localhost ~]$ ls
makeLink.sh
[auser at localhost ~]$ cat makeLink.sh 
#!/bin/sh
echo First arg is: $1, Second arg is $2
/bin/ln -s $1 $2 
[auser at localhost ~]$ mkdir foo
[auser at localhost ~]$ ./makeLink.sh foo foo\ bar
First arg is: foo, Second arg is foo bar
/bin/ln: when making multiple links, last argument must be a directory
[auser at localhost ~]$ ln -s foo boo\ hoo
[auser at localhost ~]$ ls -l
total 20
lrwxrwxrwx  1 auser auser    3 Apr 26 11:50 boo hoo -> foo
drwxrwxr-x  2 auser auser 4096 Apr 26 11:49 foo
-rwxr-xr-x  1 auser auser   68 Apr 26 11:44 makeLink.sh
[auser at localhost ~]$ ./makeLink.sh foo 'some\ thing'
First arg is: foo, Second arg is some\ thing
/bin/ln: when making multiple links, last argument must be a directory